What is the average dosage in mg/L if 1,170 lbs of lime was fed over 5 days treating 3.5 million gallons per day?

To determine the average dosage of lime in mg/L, we first need to convert the weight of lime from pounds to milligrams and the volume of water from gallons to liters.

Start with the total amount of lime fed over the treatment period:

1. Convert the lime from pounds to grams. Since there are 453.592 grams in a pound:

( 1,170 \text{ lbs} \times 453.592 \text{ g/lb} = 530,788.64 \text{ g} )

2. Convert grams to milligrams (since there are 1,000 mg in a gram):

( 530,788.64 \text{ g} \times 1,000 \text{ mg/g} = 530,788,640 \text{ mg} )

Next, calculate the total volume of water treated over the 5-day period. The daily flow rate is 3.5 million gallons:

1. For 5 days, the total volume in gallons is:

( 3.5 \text{ million gallons/day} \times 5 \text{ days} = 17.5 \text{ million gallons} )

2. Now, convert