The clearwell at a 3 MGD plant is 102 feet in diameter and 20 feet deep. What is the volume of the tank in cubic feet?

To calculate the volume of a cylindrical tank, the formula used is:

[ \text{Volume} = \pi r^2 h ]

In this case, the diameter of the clearwell is provided as 102 feet. To find the radius, you divide the diameter by 2:

[ r = \frac{102}{2} = 51 \text{ feet} ]

The depth (height) of the tank is given as 20 feet.

Now, substituting the radius and the height into the volume formula:

[ \text{Volume} = \pi (51^2) (20) ]

[ = \pi (2601) (20) ]

[ = 52020\pi ]

Using the approximate value of (\pi \approx 3.14159):

[ \text{Volume} \approx 52020 \times 3.14159 \approx 163343.34 \text{ cubic feet} ]

Rounding to the nearest whole number gives a volume of approximately 163343 cubic feet.

Thus, the correct answer is indeed appropriate based on the calculation, confirming that the volume of the clearwell is calculated accurately.