A sedimentation basin is 90 feet long, 30 feet wide, and 12 feet deep. What is the volume of the tank in cubic feet?

Prepare for the North Carolina Surface Water Math Test with detailed questions and answers. Enhance your readiness with in-depth explanations and effective study tools for a comprehensive understanding crucial for success. Get exam-ready today!

The volume of a rectangular prism, such as a sedimentation basin, can be calculated using the formula:

[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Depth} ]

In this case, the sedimentation basin has dimensions of 90 feet long, 30 feet wide, and 12 feet deep. Plugging in these values into the formula gives:

[ \text{Volume} = 90 , \text{ft} \times 30 , \text{ft} \times 12 , \text{ft} ]

Calculating step-by-step:

  1. First, multiply the length by the width:

[ 90 , \text{ft} \times 30 , \text{ft} = 2700 , \text{sq ft} ]

  1. Then, multiply the result by the depth:

[ 2700 , \text{sq ft} \times 12 , \text{ft} = 32400 , \text{cubic ft} ]

Thus, the volume of the tank is 32,400 cubic feet, which corresponds to the

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy